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MayaTekla Newbie

Joined: 20 Apr 2012 Posts: 3
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Posted: Fri Apr 20, 2012 7:46 am Post subject: [solved] (workaround) RANK function help |
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Hi All,
I have a set of data that I am attempting to rank, however the rank function causes there to be gaps in the rank numbering so for example if i have a data set:
1 3 5 7 7 10
They get ranked 1 2 2 4 5 6 (missing out the 3 and skipping onto 4!) Can anybody help me to create a formula or help write a function to do this?
I have started writing a function that does this for me in OO Basic, however I cant seem to get it to work (at least its almost there but I Just cant get the results I want)
Last edited by MayaTekla on Wed May 02, 2012 7:31 am; edited 1 time in total |
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ozzie OOo Advocate

Joined: 29 Jul 2010 Posts: 316 Location: victoria
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Posted: Fri Apr 20, 2012 8:34 am Post subject: |
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Your numbers in A1 to F1-
| Code: | | =RANK(A1;$A$1:$F$1)+COUNTIF($A$1:A1;A1)-1 |
_________________ If your problem has been solved please add "[Solved]" to the beginning of your first post title (edit button). |
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MayaTekla Newbie

Joined: 20 Apr 2012 Posts: 3
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Posted: Fri Apr 20, 2012 2:44 pm Post subject: |
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Thanks Ozzie, however this still isnt quite right
If I have a data set such as:
| Code: | Something Rank
1 6
2 5
4 4
4 4
5 2
6 1
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essentially this has changed it from two 3's to two 4's, Ideally Im after:
| Code: | Something Rank
1 5
2 4
4 3
4 3
5 2
6 1 |
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ken johnson Super User

Joined: 23 Apr 2009 Posts: 1851 Location: Sydney, Australia
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Posted: Fri Apr 20, 2012 6:33 pm Post subject: |
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If the RANK function's second parameter is changed from the full list of 'Something' to a list of 'Something's Unique Values Only' you will get the rank value you are after...
| Code: | Something Uniques Rank
1 1 5
2 2 4
4 4 3
4 3
5 5 2
6 6 1
The second 4 is not in the list of Uniques
because it occurs earlier in the Something list |
If 'Something' values are in A2:A7 the list of Uniques can be generated using...
| Code: | | =IF(COUNTIF(A$2:A2;A2)=1;A2;"") | filled down as far as required.
If the Unique values are in B2:B7, the desired ranks can be generated using Ken Johnson _________________ If your problem has been solved please add "[Solved]" to the beginning of your first post title (edit button). |
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MayaTekla Newbie

Joined: 20 Apr 2012 Posts: 3
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Posted: Wed May 02, 2012 7:30 am Post subject: |
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| Thanks John, that looks like it will do the job, can just hide the extra column. |
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ken johnson Super User

Joined: 23 Apr 2009 Posts: 1851 Location: Sydney, Australia
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Posted: Wed May 02, 2012 8:09 pm Post subject: |
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It can also be done without the extra column but then you have to use this complex array formula... | Code: | | IF(A2="";"";RANK(A2;IF($A$2:$A$7="";"";IF(MATCH($A$2:$A$7;$A$2:$A$7;0)=ROW($A$2:$A$7)-MIN(ROW($A$2:$A$7))+1;$A$2:$A$7;"")))) | where I have assumed that the list of values to be ranked occupy A2:A7. (Changing $A$2:$A$7 in the formula to a larger range to cater for a changing number of values to be ranked is OK. Using too large a range in an array formula is not a good idea though.)
Array formulae must be entered using Ctrl+Shift+Enter and when using the fill handle to fill the array formula into adjacent cells the Ctrl key must be held down while the fill handle is being dragged.
Ken Johnson _________________ If your problem has been solved please add "[Solved]" to the beginning of your first post title (edit button). |
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