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Sonic Newbie

Joined: 10 Jan 2005 Posts: 3
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Posted: Mon Jan 10, 2005 5:46 am Post subject: Function pii |
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| Why function pii() donīt work in 1.1.1 (--> #name) ? |
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David Super User


Joined: 24 Oct 2003 Posts: 5668 Location: Canada
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Posted: Mon Jan 10, 2005 7:16 am Post subject: Re: Function pii |
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| Sonic wrote: | | Why function pii() donīt work in 1.1.1 (--> #name) ? |
Note: Just one "i" in Pi(), or you get your error.
Pi() works fine in version 1.1.3. In fact, entering =pi defaults to =Pi(), and shows the value.
David. |
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Sonic Newbie

Joined: 10 Jan 2005 Posts: 3
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Posted: Mon Jan 10, 2005 10:54 pm Post subject: |
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| It doesnīt still work, if type =Pi and enter it will automatically change to =pii() and answer will bee #name? Same problem was allso in 1.1.0 (finnish version). Language it is reason why Iīm using older version 1.1.1 |
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r_vinoya Super User


Joined: 03 Dec 2003 Posts: 619 Location: Somewhere in the Philippines
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Posted: Tue Jan 11, 2005 12:16 am Post subject: |
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| Sonic wrote: | | It doesnīt still work, if type =Pi and enter it will automatically change to =pii() and answer will bee #name? Same problem was allso in 1.1.0 (finnish version). Language it is reason why Iīm using older version 1.1.1 |
You should type =pi() [with the open and close parenthesis () ] as david has suggested.
About automatically changing into =pii() that is strange. _________________ # : - ) |
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Sonic Newbie

Joined: 10 Jan 2005 Posts: 3
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Posted: Tue Jan 11, 2005 1:25 am Post subject: |
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| More strange things: if i open file which has made for example excel 97 and there is formula which incudeles function "pii()" (like you have to put it in excel) OO will calculate that all ringht but if chance anything in the formula OOīs answer will be #name? ??? And =pi() doesnīt work. |
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