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kuzhie
General User
Joined: 08 Feb 2004
Posts: 26
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 Posted: Tue Mar 23, 2004 3:08 pm Post subject: instantiate SimpleFileAccess in java |
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Helloo!
Being a newbie, OO API seems to look very complex. This is what I dont understand. How can I know the right way to instantiate an object in java.
I have a sample code in Basic such as
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oSimpleFileAccess = createUnoService( "com.sun.star.ucb.SimpleFileAccess" )
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In my java, I've try
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String storeFileUrl = "file:////home/kusumas/Java/Receipt/MyFile.pdf"
xSimpleFileAccess = (com.sun.star.ucb.XSimpleFileAccess)UnoRuntime.queryInterface(
com.sun.star.ucb.XSimpleFileAccess.class, desktop);
xSimpleFileAccess.openFileRead(storeFileUrl);
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But on the line 'openFileRead' I got null (java.lang.NullPointerException) error.
I have other object such as XInputStream and XOutputStream that I'd like to try on my applicaiton. But I'm not sure how can I use such object.
TIA for any input,
Kusuma |
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DannyB
Moderator
Joined: 02 Apr 2003
Posts: 3991
Location: Lawrence, Kansas, USA
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