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Cham
Newbie
Joined: 01 Aug 2008
Posts: 3
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 Posted: Fri Aug 01, 2008 6:30 pm Post subject: Need help with data manipulation in NeoOffice |
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I need help with some data manipulation in NeoOffice. I am not an expert with spreadsheet apps  I have a LARGE bunch of mixed numbers (three cartesian coordinates) and text, like this very small sample :
| Code: | vertices $
0.587341 -0.004852 0.809325
0.587344 0.003316 0.809330
0.589727 0.017470 0.807414
0.593521 0.029771 0.804268
linestrip $
vertices $
0.489287 -0.011868 0.872042
0.480151 -0.042015 0.876179
0.477583 -0.056780 0.876750
0.481149 -0.062965 0.874375
0.503490 -0.080895 0.860206
0.505628 -0.091953 0.857838
0.506437 -0.106646 0.855657
linestrip $
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I need to replace each $ with the number of points (an integer) enclosed within the words "vertices" and "linestrip". In this example, I want to get this :
| Code: | vertices 4
0.587341 -0.004852 0.809325
0.587344 0.003316 0.809330
0.589727 0.017470 0.807414
0.593521 0.029771 0.804268
linestrip 4
vertices 7
0.489287 -0.011868 0.872042
0.480151 -0.042015 0.876179
0.477583 -0.056780 0.876750
0.481149 -0.062965 0.874375
0.503490 -0.080895 0.860206
0.505628 -0.091953 0.857838
0.506437 -0.106646 0.855657
linestrip 7
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Next, I need to replace each empty line below the "linestrip" with integers from 0, 1, 2, ... to $-1, like this :
vertices 4
| Code: | 0.587341 -0.004852 0.809325
0.587344 0.003316 0.809330
0.589727 0.017470 0.807414
0.593521 0.029771 0.804268
linestrip 4
0
1
2
3
vertices 7
0.489287 -0.011868 0.872042
0.480151 -0.042015 0.876179
0.477583 -0.056780 0.876750
0.481149 -0.062965 0.874375
0.503490 -0.080895 0.860206
0.505628 -0.091953 0.857838
0.506437 -0.106646 0.855657
linestrip 7
0
1
2
3
4
5
6
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Someone knows how to do this, in OpenOffice (I'm using the OS X version) ? |
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RickRandom
Super User
Joined: 27 Jan 2006
Posts: 1082
Location: UK
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| Posted: Sat Aug 02, 2008 12:01 am Post subject: |
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It's a bit clumsy, but:
With the first word "vertices" in cell A2, and the data in columns A, B and C:
Put in D2:
=if(A2="vertices";0;if(A2="linestrip";D1;if(and(A1="linestrip";isblank(A2));0;D1+1)))
and copy down as far as necessary.
Put in E2:
=if(A2="vertices";vlookup("linestrip";A3:$D$21;4;TRUE);if(A2="linestrip";D1;if(isnumber(B2);B2;D2)))
and copy down as far as necessary. (Adjust the $D$21 to cover the size of your data.)
This gives you a new column to use instead of column B.
Let us know if this works, but I think this would be better done in a programming language (not that I could do it.  ) |
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Cham
Newbie
Joined: 01 Aug 2008
Posts: 3
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| Posted: Sat Aug 02, 2008 5:34 am Post subject: |
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Thanks a lot for your reply !
The first instruction (in D2) is working, apparently. At least, it's giving me a column of integers... But when I insert the other instruction in cell E2, I'm getting a #NAME? and I'm unable to get it to work (this is one thing I never understood clearly in OpenOffice).
Also, should I remove all the $ in my data ? |
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